请教一段关于AK, AA/KK的计算

今天看到这个：

If we are dealt AdKd, the number of combinations of AA and KK our opponent can have drops from 12 to 6. Since the number of possible combinations drop from 1326 -101= 1225 (there are 51 combinations each with Ad or Kd, which makes a total of 101 unique combinations containing Ad or Kd, since we count AdKd only once), the chance our opponent has AA or KK is 1/204 or 0.5%.

如果是HU，我们拿到AK，对手拿AA or KK的机率是大约0.5%吗？